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  1. Arduino IDE 2.3.4 is now available - IDE 2.x - Arduino Forum

    Dec 5, 2024 · Deprecation notice: Upcoming cessation of support for Linux distros using glibc 2.28 Recent changes in the framework used to produce automated release of Arduino IDE …

  2. Latest Français topics - Arduino Forum

    Nov 2, 2025 · Making embedded systems accessible to allTutoriels et cours Cours et tutoriels autour de l’Arduino Le bar -- Espace détente -- Réalisations et Projets Finis Ce sous forum est …

  3. Arduino IDE 2.3.5 is now available - IDE 2.x - Arduino Forum

    Apr 2, 2025 · Arduino IDE will now gracefully handle invalid " Additional Boards Manager URLs " preference data. Of course, the dependent boards platform will still not be available for …

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    Making embedded systems accessible to all

  5. Latest Deutsch topics - Arduino Forum

    5 days ago · Making embedded systems accessible to all

  6. Latest Community topics - Arduino Forum

    Oct 24, 2025 · This board is just to let us know about bugs on create.arduino.cc/projecthub, thank you for reporting any issue or for sharing any idea. Suggestions for the Arduino Project What …

  7. Arduino IDE 2.0.0 available for download!

    Sep 14, 2022 · From a functional standpoint, this release is equivalent to 2.0.0-rc9.4. It serves the important purpose of marking the end of the pre-release development phase of the Arduino …

  8. Arduino IDE 2.2.1 is now available - IDE 2.x - Arduino Forum

    Sep 1, 2023 · This is a minimal bugfix patch release. If you are upgrading from Arduino IDE 2.1.1, please also check the more significant changelog for the 2.2.0 release:

  9. Latest Español topics - Arduino Forum

    Oct 20, 2025 · Este es el foro General.<br> Aquí deben postearse los temas cuando no se haya determinado correctamente la categoría que le corresponde a su consulta.<br> Habitualmente …

  10. IF with AND and OR fuctions - Syntax & Programs - Arduino Forum

    Dec 2, 2010 · With my BASIC language programmed controllers I can use AND and OR. example: IF (VAL > 100 AND VAL < 140) THEN ... How can I solve this with the if function in …